9x/x^2+8x

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Solution for 9x/x^2+8x equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

8*x+(9*x)/(x^2) = 0

8*x^1+9*x^-1 = 0

(8*x^2+9*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^2+9*x^0) = 0

x^1

8*x^2+9 = 0

8*x^2+9 = 0

DELTA = 0^2-(4*8*9)

DELTA = -288

DELTA < 0

x in { } 

x belongs to the empty set

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